問題已解決
(5500+A+16500)/(8250+B)=3 (5500+A)/(8250+B)=1.5 怎么解這個二元一次方程
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您好!很高興為您解答,請稍等
2024 09/02 20:26
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廖君老師 ![](/wenda/_nuxt/img/reply2.28c7604.png)
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2024 09/02 20:34
您好,(5500+A+16500)/(8250+B)=3 整理為 22000+A=24750+3B
(5500+A)/(8250+B)=1.5? 整理為 5500+A=12375+1.5B
兩個等式都有A相減 22000-5500=24750+3B-12375-1.5B,整理16500=12375+1.5B,整理16500-12375=1.5B,解得B=(16500-12375)/1.5=2750,代入 (5500+A)/(8250+2750)=1.5 計算A=11000
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